A hydrocarbon contains $$85$$. $$7$$% C. If $$42$$ mg of the compound contains $$3.01$$ x $$1020$$ molecules, the molecular formula of the compound will be:

Question

A hydrocarbon contains $$85$$. $$7$$% C. If $$42$$ mg of the compound contains $$3.01$$ x $$1020$$ molecules, the molecular formula of the compound will be:

Infinity Learn · Accepted Answer

Given $$3.01$$ x  $$1020$$ molecules weigh  $$42$$ x  $$10$$–$$3$$ $$g6.02$$ x  $$1023$$ molecules weigh  ‘X’ gX  $$=$$   $$84$$ g∴ Molar mass of Hydrocarbon is $$84$$ gramsBy Inspection :Molar mass of   $$C6H12=612$$  $$+$$  $$121g$$                                                  $$=$$ $$84$$ gAlternate Method:–                                           C              :        HMass Ratio                  $$85.7$$                      $$14.3Gram$$ atom ratio        $$85.712$$                    $$14.31Gram$$ atom ratio          $$7.14$$                     $$14.3Gram$$ atom ratio          $$7.147.14=1$$            $$14.37.14=2Empirical$$ formula of Hydrocarbon $$=$$ $$CH2EFW$$ $$=$$ [$$12$$ $$+$$ $$2(1)$$]g  $$=$$  $$14gMFW$$ $$=$$ $$84gNumber$$ of EF in a given MF $$=$$  $$MFWEFW=8414=6$$ ∴     MF  $$=$$   $$CH26=C6H12$$

A hydrocarbon contains 85. 7% C. If 42 mg of the compound contains 3.01 x 1020 molecules, the molecular formula of the compound will be:

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