Q.
In hydrogen atom an electronic transition starts from the orbit having radius 1.3225 nm and ends at an orbit with 211.6 pm . The region of spectrum is
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answer is 1.
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Detailed Solution
rn= 0.0529 nm × n2 =1.32250.0529=25⇔n=5 rn = 52.9 pm × n2 =211.652.9=4⇔ n=2 Transition is from n =5 to n =2 Balmer series, visible region
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