In hydrogen atom an electronic transition starts from the orbit having radius 1.3225 nm and ends at an orbit with 211.6 pm . The region of spectrum is

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

rn= 0.0529 nm × n2 =1.32250.0529=25⇔n=5 rn = 52.9 pm × n2 =211.652.9=4⇔ n=2 Transition is from n =5 to n =2 Balmer series, visible region

Watch 3-min video & get full concept clarity