First slide

Nernst Equation

Question

The hydrogen electrode is dipped in a solution of pH = 3 at 25⁰C. The potential of the cell would be (value of 2.303 RT/F is 0.059 V)

Easy

Solution

${p^H} = \frac{{ - {E_{RP}}}}{{0.0591}} \Rightarrow {E_{RP}} = - 3\left( {0.0591} \right) = - 0.177V$

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