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Q.

A hydrogen electrode is dipped in a solution of pH = 3.0 at 25oC. The potential of the cell will be

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a

0.177 V

b

0.087 V

c

-0.177 V

d

0.059 V

answer is C.

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Detailed Solution

H++e−→12H2(g)E=Eo−0.059nlog⁡1(H+)=0−0.0591pHOr E=−0.059×3=−0.177 V
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