A hydrogen gas electrode is made by dipping platinum wire in a solution of HCI and pH = 10 and by passing hydrogen gas around the platinum wire at 1 atm pressure. The oxidation potential of electrode would be

For hydrogen electrode, oxidation half-reaction is H2(1 atm )⟶2H+ at pH10+2e− If pH=10,H+=1×10−pH=1×10−10From Nernst equation, E=E∘−0.05912log⁡H+2pH2For hydrogen electrode, E∘=0E=−0.05912log⁡10−1021=−0.0591×22log⁡(10)−10   =0.0591×10×log⁡10=0.59V