Hydrolysis of an alkyl halide (RX) by dilute alkali [O⊝H] takes place simultaneously by SN2 and SN1 pathways.A plot of −1[RX]d[R−X]dt vs [OH] is a straight line of the slope equal to 2 × 103 mol-1 L h-1 and intercept equal to 1 × 102 h-1. Calculate the initial rate (mole L-1 min-1 ) of consumption of RX when the reaction is carried out taking.1molL−1 of RX and 0.1molL−1 of [OH] ions.

−d[RX]dt=k2[RX][OH]k2= rate constant of SN2 reaction −d[RX]dt=k1[RX]k1= rate constant of SN1 reaction −d[RX]dt=k2[RX][OH]+k1[RX]−1[RX]d[RX]dt=k2[OH]+k1This is the equation of a straight line for −1[RX]d[RX]dt vs  [OH] plot with slope equal to k2 and intercept equal to k1. From question:k2=2×103mol−1Lhr−1,k1=1×102hr−1[RX]=1.0M and [O⊝H]=0.1MHence, −d[RX]dt=2×103×1×0.1+1×102×1=300molL−1hr−1=5molL−1min−1