First slide

Ionization constants of weak acids, PH of weak acids

Question

The hydrolysis constant of MX is $(Given K_{b} of MOH is 2 \times 10^{- 6} and K_{a} of HX is 5 \times 10^{- 7})$

Easy

Solution

$\large \\{K_h} = \frac{{{K_w}}}{{{K_a} \times {K_b}}}\\\\{K_h} = \frac{{{{10}^{ - 14}}}}{{5 \times {{10}^{ - 7}} \times 2 \times {{10}^{ - 6}}}} = {10^{ - 2}}$

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