Hydrolysis of methyl acetate in aqueous solution has been studied by titrating acetic acid against NaOH. The concentration of ester at different times is given below.The concentration of water remain constant at 55 M. Find Rate constant (K)?
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a
3×10-2 min-1
b
5.4×10-4 min-1
c
3×10-2 lit/mole/min
d
5.4×10-4 lit/mole/min
answer is D.
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Detailed Solution
KH2O=2.303tlogaa-xKH2O=2.30323.03log4020=0.03Average value for different time intervals K[H2O] = 0.03 min-1It is pseudo first order reactionK100018 = 0.03K = 5.4×10-4 lit/mole/min