A hypothetical reaction X2 + Y2 ➔ 2XY follows the mechanism as given belowX2⇌X+X( fast )X+Y2⟶XY+Y (slow) X+Y⟶XY (fast) Order of the reaction is
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a
1
b
2
c
32
d
Zero
answer is C.
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Detailed Solution
Slow step reaction is rate determining step.X+Y2⟶XY+Y (slow) r=K[X]Y2Put the value [X] from first fast reactionr=K12KX212Y2K′=K12×Kr=K11=X212Y2=32Overall order of reaction is 32.