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Q.

I g of the carbonate of a metal was dissolved in 25 mL of N-HCI. The resulting liquid required 5 mL of N-NaOH for neutralisation.The Ew of the metal carbonate is

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a

50

b

30

c

20

d

None

answer is A.

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Detailed Solution

Total HCl ⇒25 x 1 = 25 mEqExcess HCl ⇒ 5 x 1 = 5 mEqHCl used ⇒ 25 - 5 = 20 mEq∴mEq of HCl = mEq of carbonate201000Eq= Weight Ew of carbonate =1Ew∴Ew=100020=50

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