i) H2O2→ H2O+Oii) H2O2+2I−→ I2+2OH− H2O2 acts as

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oxidising agent in both (i) and (ii)

reducing agent in both (i) and (ii)

oxidising agent in (i) and reducing agent in (ii)

reducing agent in (i) and oxidising agent in (ii)

answer is A.

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Detailed Solution

In first reaction H2O2 donating oxygen. In second reaction Iodine oxidation state changes from -1 to 0.

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