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Q.

I mole of CaCO3(s) is heated in 11.2 Lit vessel so that equilibrium is established at 819 Kelvin. If KP for CaCO3(s)⇌CaO(s)+CO2(g) at this temperature is 2 atm, equilibrium active mass of CO2( g)  is ____?

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a

13

b

111.2

c

133.6

d

122.4

answer is C.

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Detailed Solution

According to given equilibrium reactionKP=PCO2 Partial pressure of CO2=2atmby taking ideal gas equation(2)(11.2)=n×0.0821×819n = 0.333 active mass =0.333 mole 11.2 lit =133.6 mole.lit -1
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