(I) Propene →HCl X (major) ;(II) Propene →(C6H5CO)2OHCl Y (major) ;Correct statement about  X and Y is

HCl will not show peroxide effect.Peroxide cannot break strong H-Cl bond into free radicals.Reaction of alkenes with HCl gives Markovnikov's product always.CH3-CH=CH2→presence or absence of peroxideHCl CH3-CHCl-CH3major