I.ZnSO4(aq)+2NH4OH(aq)⟶Zn(OH)2(s)+NH42SO4(aq) AII.FeCl3(aq)+3NH4OH(aq)⟶Fe2O3⋅xH2O(s)+NH4Cl(aq) B The colours of compounds A and B respectively are

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brown and white

brown and brown

white and brown

white and white

answer is C.

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Detailed Solution

(i) ZnSO4(aq)+2NH4OH(aq)⟶Zn(OH)2(s)+NH42SO4(aq)(white ppt. )(ii) FeCl3(aq)+NH4OH(aq)⟶Fe2O3⋅xH2O(s) +NH4Cl(aq) (Brown ppt.)

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