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An ideal gas is allowed to expand in a well insulated container against a constant external pressure of 5 atm from an initial volume of 8 litres to final volume of 10litres. Change in internal energy is

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answer is 3.

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Detailed Solution

Wirr=-Pext(vf-vi)  = −510-8 = − 10  lit−atm Wirr= −10101J        = - 1010 J ΔU = q+w q = 0, for insulated vessel Δu  =  w  =  −1010  J
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