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Q.

For an ideal gas, consider only P-V work in going from an initial state X to the final state Z. The final state Z can be reached by either of the two paths shown in the figure.Which of the following choice(s) is(are) correct'?[Take ∆S as change in entropy and w as work done].

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a

ΔSx→z=ΔSx→y+ΔSy→z

b

wx→z=wx→y+wy→z

c

wx→y→z=wx→y

d

ΔSx→y→z=ΔSx→y

answer is A.

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Detailed Solution

1) ΔSx→z=ΔSx→y+ΔSy→z(because entropy is a state function and hence additive)2) wx→z≠wx→y+wy→z3) wx→y→z=wx→y (because wy→z=0 as it is an isochoric process) 4) ΔSx→y→z≠ΔSx→y but =ΔSx→y+ΔSy→zThus, only (1) and (3) are correct

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