Identify the correct statements from the following.
A) P-Cl_axial bond is shorter than P-Cl_equatorial bond in PCl₅(g) molecule.
B) Hybridization of Phosphorous in PCl₅(s) is sp³d.
C) POCl₃ is the intermediate formed during the hydrolysis of PCl₅.
D) PCl₅ oxidizes Sn to SnCl₄.

Question

Identify the correct statements from the following.

A) P-Cl_axial bond is shorter than P-Cl_equatorial bond in PCl₅(g) molecule.

B) Hybridization of Phosphorous in PCl₅(s) is sp³d.

C) POCl₃ is the intermediate formed during the hydrolysis of PCl₅.

D) PCl₅ oxidizes Sn to SnCl₄.

Infinity Learn · Accepted Answer

$$A)$$ $$P-Claxial$$ bond is longer than $$P-Clequatorial$$ bond in $$PCl5g$$ molecule.    Axial bonds experience more repulsions than equatorial bonds.$$B)$$ Hybridization of Phosphorous in $$PCl5(s)$$ is $$sp3$$ and $$sp3d2$$.    Solid $$PCl5$$ exists as $$PCl4+PCl6-$$    In $$PCl4+$$ the hybridization of ‘P’  is $$sp3$$ and in $$PCl6-it$$ is $$sp3d2$$.$$C)$$ $$POCl3$$ is the intermediate formed in the hydrolysis of $$PCl5$$.$$PCl5+H2O$$ →$$POCl3+2HCl$$ ; $$POCl3+3H2O$$ →$$H3PO4+3HCl$$ ; $$D)$$ $$PCl5$$ oxidizes Sn to $$SnCl4$$ at itself gets reduced to $$PCl3$$.

Identify the correct statements from the following.
A) P-Cl_axial bond is shorter than P-Cl_equatorial bond in PCl₅(g) molecule.
B) Hybridization of Phosphorous in PCl₅(s) is sp³d.
C) POCl₃ is the intermediate formed during the hydrolysis of PCl₅.
D) PCl₅ oxidizes Sn to SnCl₄.

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Identify the correct statements from the following.A) P-Claxial bond is shorter than P-Clequatorial bond in PCl5(g) molecule.B) Hybridization of Phosphorous in PCl5(s) is sp3d.C) POCl3 is the intermediate formed during the hydrolysis of PCl5.D) PCl5 oxidizes Sn to SnCl4.

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Ready to Test Your Skills?

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Identify the correct statements from the following.
A) P-Cl_axial bond is shorter than P-Cl_equatorial bond in PCl₅(g) molecule.
B) Hybridization of Phosphorous in PCl₅(s) is sp³d.
C) POCl₃ is the intermediate formed during the hydrolysis of PCl₅.
D) PCl₅ oxidizes Sn to SnCl₄.