Identify the correct statements from the following.A) P-Claxial bond is longer than P-Clequatorial bond in PCl5(g) molecule.B) Hybridization of Phosphorous in PCl5(s) is sp2.C) POCl3 is the intermediate formed during the hydrolysis of PCl5.D) PCl5 oxidizes Ag to AgCl.

A) P-Claxial bond is longer than P-Clequatorial bond in PCl5g molecule.    Axial bonds experience more repulsions than equatorial bonds.B) Hybridization of Phosphorous in PCl5(s) is sp3 and sp3d2.    Solid PCl5 exists as PCl4+PCl6-    In PCl4+ the hybridization of ‘P’  is sp3 and in PCl6-it is sp3d2.C) POCl3 is the intermediate formed in the hydrolysis of PCl5.PCl5+H2O →POCl3+2HCl ; POCl3+3H2O →H3PO4+3HCl ; D) PCl5 oxidizes Ag to AgCl at itself gets reduced to PCl3.