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a
Yb+2Z=70……diamagnetic
b
CuI2………. Stable
c
Cu+aq…….undergoes disproportionation
d
VF5……..can exist
answer is B.
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Detailed Solution
1Yb(Z=70)......[Xe]4f145do6s2Yb+2.....[Xe]4f14.....n=0....diamagnetic(2) CuI2 is unstable 2Cu+2+4I− → Cu2I2+I2(3) 2Cu+ → Cu+2+Cu........In aqueous solution(4) VF5 is stable due to high BDE