First slide

Diborane

Question

Identify X and Y in the following reaction.
$\large BCl_3 + NH_4Cl \xrightarrow[{C_6H_5Cl}]{{140^o}}\ X \xrightarrow{NaBH_4} Y$

Moderate

A

X = NaBO₂, Y = B₂O₃
B

Na₂B₄O₇, Y = H₃BO₃
C

X = BN, Y = [NH₄] + [BCl₄]^–
D

X = B₃N₃H₃Cl₃, Y = B₃N₃H₆

Solution

$\large 3BC{l_3} + 3N{H_4}Cl\xrightarrow[{{{140}^0}C}]{{{C_6}{H_5}Cl}}\mathop {\mathop {{B_3}{N_3}{H_3}C{l_3}}\limits_{OR} }\limits_{{{(BNHCl)}_3}} + 9HCl$
$\large \mathop {\mathop {{B_3}{N_3}{H_3}C{l_3}}\limits_{OR} }\limits_{{{(BNHCl)}_3}} \xrightarrow{{3NaB{H_4}}}\mathop {{B_3}{N_3}{H_6}}\limits_{Borazine} + 3NaCl + 3B{H_3}$
Ammonium chloride reacts with boron trichloride at 140⁰ C in presence of chlorobenzene as catalyst to produce trichloro borazine ,which on reduction with NaBH₄ gives borazine.

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