IE1 and IE2 of Mg are 178 and 348 kcal mol−1. The energy required for the ionisation as shown is, Mg⟶Mg2++2e−is (in same units)
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a
+170
b
+526
c
-170
d
-526
answer is B.
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Detailed Solution
(i) Mg(g)⟶Mg(g)⊕+e−, IE1=178 kcal mol−1 (ii) Mg(g)⊕⟶Mg(g)2++e− IE2=348 kcal mol−1Adding (i) and (ii), we haveMg(g)⟶Mg2+(g)+2e−∴E=IE2+IE2=178+348=526kcal