First slide
Periodicity in atomic properties
Question

IE1 and IE2 of Mg are 178 and 348 kcal mol-1. The energy required for the reaction MgMg2++2e- is __________.

Easy
Solution

 (i) Mg(g)Mg(g)+e, IE1=178 kcal mol1

 (ii) Mg(g) Mg2+(g)+e, IE2=348kcalmol1

Adding (i) and (ii), we have

---------- Mg(g)Mg2+(g)+2e ----------

 E = IE1 + IE2 = 178 +348 =526 kcal

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