Periodicity in atomic properties

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Question

IE₁ and IE₂ of Mg are 178 and 348 kcal mol^-1. The energy required for the reaction $Mg \to {Mg}^{2 +} + 2 e^{-}$ is __________.

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Solution

$(i) {Mg}_{(g)} ⟶ {Mg}^{\oplus}_{(g)} + e^{-}, {IE}_{1} = 178 kcal {mol}^{- 1}$
$(ii) \underset{}{{Mg}^{\oplus}_{(g)}} ⟶ {Mg}^{2 +}_{(g)} + e^{-}, {IE}_{2} = 348 kcal {mol}^{- 1}$
Adding (i) and (ii), we have
$- - - - - - - - - - {Mg}_{(g)} ⟶ {Mg}^{2 +}_{(g)} + 2 e^{-} - - - - - - - - - -$
$∴$ E = IE₁ + IE₂ = 178 +348 =526 kcal

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Periodicity in atomic properties

Unlock the full solution & master the concept.

IE1 and IE2 of Mg are 178 and 348 kcal mol-1. The energy required for the reaction Mg→Mg2++2e- is __________.

(i) Mg(g)⟶Mg⊕(g)+e−, IE1=178 kcal mol−1 (ii) Mg⊕(g) ⟶Mg2+(g)+e−, IE2=348kcalmol−1Adding (i) and (ii), we have---------- Mg(g)⟶Mg2+(g)+2e− ----------∴ E = IE1 + IE2 = 178 +348 =526 kcal

Ready to Test Your Skills?

free study material

IE₁ and IE₂ of Mg are 178 and 348 kcal mol^-1. The energy required for the reaction $Mg \to {Mg}^{2 +} + 2 e^{-}$ is __________.