If the atomic weight of an element is 4 times that of the Helium and it has 8 protons, then it contains

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8 protons, 16 neutrons,8 electrons

8 protons, 8 neutrons,8 electrons

16 protons, 32 neutrons,8 electrons

8 protons, 8 neutrons,16 electrons

answer is B.

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Detailed Solution

Given, Atomic mass= mass no. (A)=4 times that of the Helium=4(4)=16Atomic no.(Z)=8=no. of protons = no. of electrons (Since it is a neutral species)no. of neutrons=A-Z=16-8=8

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