Q.

If bond dissociation energies of N≡N, H-H, and N-H are x1, x2 and x3 respectively, hence enthalpy of formation of NH3(g) is

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a

x1+3x2−6x3

b

3x3−12x1−32x2

c

x12+32x2−3x

d

6x3−x1−3x2

answer is C.

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Detailed Solution

12N2(g)+32H2(g)→NH3(g)ΔrH=ΔformHNH3,gΔformHNH3,g=12DN≡N+32DH−H−3DN−H=12×x1+32x2−3x3
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