First slide

Enthalpy of Atomisation and bond dissociation

Question

If the bond energies of H–H, Br-Br and H-Br are 433, 192 and 364 kJ mol^–1 respectively, then ΔH⁰ for the reaction :
H_2(g) + Br_2(g) → 2HBr_(g) is

Moderate

Solution

$\begin{array}{l} \Delta H = \sum B{E_{reac\tan ts}} - \sum B{E_{products}}\\ \,\,\,\,\,\,\,\,\, = B{E_{H - H}} + B{E_{Br - Br}} - 2B{E_{H - Br}}\\ \,\,\,\,\,\,\,\,\, = 433 + 192 - 2(364)\\ \,\,\,\,\,\,\,\,\,\, = - 103KJ \end{array}$

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