If the bond enthalpy of O2, N2 and H2 are 498 kJ mol-1, 946 kJ mol-1 and 435.8 kJ mol-1respectively. Choosethe correct order of decreasing bond strength.
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a
H2>N2>O2
b
N2>O2>H2
c
O2>H2>N2
d
H2>O2>N2
answer is B.
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Detailed Solution
Larger the bond dissociation enthalpy stronger will be the bond in the molecule so, N2 > O2 > H2946kJ 498kJ 435.8kJ