If calcium crystallizes in BCC arrangement and the radius of Ca atom is 96 pm, and the volume of unit cell of Ca is x×10-30 m3. Find the value of x.

For BCC Lattice,  3a=4R ⇒a=4×963pm = 221.7 pm(where R is the radius of Ca atom)Volume of unit cell=a3=211.7×10-123 m3=10.9×10-30 m3Thus, 10.9×10-30=x×10-30 x = 10.9