If 0.5 A current is passed through acidified silver nitrate solution for 10 minutes. The mass of silver deposited on cathode, is (eq. wt. of silver nitrate = 108)

Given I=0.5 ampt=10×60sec⁡Q=I×t=0.5×10×60=300 CAgNO3→Ag++NO3−Anode: NO3−→1e−+NO2+12O21F→1 mole of Ag1F→108 g of Ag96500 C→108 g of Ag300 C  →300×10896500g of AgO=0.336 gm