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Q.

If  EFe+2/Fe0=x1V ,  EFe+3/Fe+20=x2V . What is the value of  EFe+3/Fe0

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a

2x1+x24

b

2x1+x23

c

2x1+x22

d

2x1+x2

answer is B.

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Detailed Solution

Fe+2+2e−→Fe;E10=x1----(1)Fe+3+e−→Fe+2;E20=x2----(2)------------------------------------------------------------------------Fe+3+3e−→Fe;E30=?E30=n1E10+n2E20n3       =2x1+x23
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