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If E = number of lone pairs of electrons of Xe, B = the number of bonding pairs of electrons, S = shape of the molecule, then, the correct set of E, B, and S of XeF4

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a

E→4 B→2 S→square planar

b

E→3 B→3 S→octahedral

c

E→3 B→3 S→ square planar

d

E→2 B→4 S→square planar

answer is D.

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Detailed Solution

XeF4Number of electron pairs =12(8+4-0+0)= 6(sp3d2)Number of bond pairs = 4Number of lone pair = 6-4 = 2XeF4.....4BP+2LP...square planarmolecule of the type AB4E2

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