Q.

If electrolysis of CuSO4 solution is carried out with 100g impure Cu as anode of 90% purity and pure Cu of mass 1009 as cathode by passing 2 amp. current for 9650 sec. Then mass of cathode and anode will be: (At. mass of Cu = 63)

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a

112.6 g and 112.6 g

b

106.3 g and 93 g

c

112.6 g and 86 g

d

172.6 g and 114 g

answer is B.

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Detailed Solution

QF=IEF=2×965096500=0.2At cathode Cu2+ + 2e- → Cu 0.1 mole depositedWeight of cathode = 100 +0.1 x 63= 106.3 gmAt anode Cu + Cu2+ + 2e- Weight of anode =100−0.1×63×10090= 93 gm
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