Q.

If the electron of a hydrogen atom is present in the first orbit, the total energy of the electron is

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a

-e2/r

b

-e2/r2

c

-e2/2r

d

-e2/2r2

answer is C.

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Detailed Solution

T.E = P.E + K.E TE=-e2r+e22r TE=-e22r
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