Q.
If the electron of a hydrogen atom is present in the first orbit, the total energy of the electron is
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a
-e2/r
b
-e2/r2
c
-e2/2r
d
-e2/2r2
answer is C.
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Detailed Solution
T.E = P.E + K.E TE=-e2r+e22r TE=-e22r
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