Q.

If electronegativity of A is 2.0 and that of B is 3.0, what is the covalent character percentage of the bond A-B?

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a

19.5%

b

80.5%

c

46%

d

54%

answer is B.

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Detailed Solution

Hanny- Smith formula% of ionic character = 16(XA-XB) +3.5(XA-XB)2                             = 16(3-2) +3.5(3-2)2                             = 16+3.5                             = 19.5%Hence % of covalent character = 100 -19.5 =80.5 %
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