If the electronic configuration of an element is 1s22s22p63s23p63d24s2, the four electrons involved in chemical bond formation will be
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a
3p6
b
3p6,4s2
c
3p6,3d2
d
3d2,4s2
answer is D.
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Detailed Solution
The given electronic configuration shows that the element is titanium (Z = 22).It belongs to d-block of the periodic table. In transition elements, i.e. d-block elements, electrons of ns and (n - l) d- subshell take part in bond formation.Hence, 3d2,4s2 contain 4 electrons which will be involved in chemical bond formation.