If electrostatic potential energy between the two electrons is $$7.67$$×$$10$$−$$19$$ J. What is their distance of separation (in$$ $$Ao) in vacuum?

Classical atomic models

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Question

If electrostatic potential energy between the two electrons is $7.67 \times 10^{- 19} J$ . What is their distance of separation (in $\overset{o}{A}$ ) in vacuum?

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Solution

$\begin{array}{l} Q = K \frac{q_{1} q_{2}}{d} or 7 .67 \times 10^{- 12} = \frac{{(1 .6 \times 10^{- 12})}^{2}}{4 \times 3 .14 \times 8.85 \times 10^{- 12} \times d} \\ K = \frac{1}{4 π \in_{0}} \\ ∴ d = 3 \times 10^{- 10} m = 3 Å \end{array}$ he permittivity of free space (a vacuum) is a physical constant equal to approximately 8.85 x 10^-12 farad per meter (F/m).

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Classical atomic models

Unlock the full solution & master the concept.

If electrostatic potential energy between the two electrons is 7.67×10−19 J. What is their distance of separation (in Ao) in vacuum?

Q=Kq1q2d or 7.67×10−12=1.6×10−1224×3.14×8.85×10−12×dK=14π∈0∴ d=3×10−10 m=3Åhe permittivity of free space (a vacuum) is a physical constant equal to approximately 8.85 x 10-12 farad per meter (F/m).

Ready to Test Your Skills?

free study material

If electrostatic potential energy between the two electrons is $7.67 \times 10^{- 19} J$ . What is their distance of separation (in $\overset{o}{A}$ ) in vacuum?