If the elevation in boiling point of a solution of 10 g of solute (molecular weight = 100) in 100 g of water is ∆Tb , the ebullioscopic constant of water is

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100Tb

∆Tb

∆Tb100

answer is C.

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Detailed Solution

∆Tb=1000×Kb×wW×M =1000×Kb×10100×100,∆Tb=KbHere, Kb = ebullioscopic constant

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