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If the equilibrium constant for $N_{2 (g)} + O_{2 (g)} ⇌ 2 {NO}_{(g)}$ is K, the equilibrium constant for $\frac{1}{2} N_{2 (g)} + \frac{1}{2} O_{2 (g)} ⇌ {NO}_{(g)} will be$

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Correct option is D

If the reaction is multiplied by 12, then new equilibrium constant, K'=K1/2N2+O2⇌2NO K=NO2N2O2 12N2+12O2⇌NO K'=NON212O212Therefore,K'=K12

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If the equilibrium constant for N2(g)+O2(g)⇌2NO(g) is K, the equilibrium constant for12 N2(g)+12O2(g)⇌NO(g) will be

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If the equilibrium constant for $N_{2 (g)} + O_{2 (g)} ⇌ 2 {NO}_{(g)}$ is K, the equilibrium constant for $\frac{1}{2} N_{2 (g)} + \frac{1}{2} O_{2 (g)} ⇌ {NO}_{(g)} will be$