Q.
If first ionization potential of a hypothetical atom is 16 V, then the first excitation potential will be
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a
10.2 V
b
12 V
c
14 V
d
16 V
answer is B.
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Detailed Solution
Given, I.P1=16eV E1=-IP1=-16eV First excitation is 2→1 En=E1n2=-16n2 E2→1=161n12-1n22=1611-14=16×34=12eV
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