If 75% of a first order reaction was completed in 90 minutes, 60% of the same reaction would be completed in approximately (in minutes)

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answer is 60.

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Detailed Solution

Use direct formulae:tx%ty%=log100100−xlog100100−yt75%t60%=2log2log2.590t60%=2×0.30.4⇒t60%=90×46=60min

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