If 75% of a first order reaction was completed in 90 minutes, 60% of the same reaction would be completed in approximately (in minutes) _______________ .(Take : log 2 = 0.30; log 2.5 = 0.40)
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Detailed Solution
t3/4=90 minutes t 1/2=t3/42=45 minutes ln245t=ln10040 t=45ln(2.5)ln2 t=45×log2.5log2=45×0.40.3=60min