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Q.

If 60% of a first-order reaction was completed in 60min , 50% of the same reaction would be completed in approximately

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a

45 min

b

60 min

c

40 min

d

50 min

answer is A.

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Detailed Solution

t=2.303Klogaa-x t60%=2.303Klog 10040----(1) t50%=2.303Klog10050----(2) (1)(2)⇒60t50%=0.400.310 t50%=45 min
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