If α is the fraction of HI dissociated at equilibrium in the reaction, 2HI⇌H2(g)+I2(g) , starting with 2 moles of HI ,the total number of moles of reactants and products at equilibrium are

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1+α

2+2α

2−α

answer is C.

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Detailed Solution

2HI⇌H2(g)+I2(g) 2−2α α α ….. Moles at equilibriumTotal no. of moles =2−2α+α+α=2 .

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