Q.
If α is the fraction of HI dissociated at equilibrium in the reaction, 2HI⇌H2(g)+I2(g) , starting with 2 moles of HI ,the total number of moles of reactants and products at equilibrium are
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a
1+α
b
2+2α
c
2
d
2−α
answer is C.
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Detailed Solution
2HI⇌H2(g)+I2(g) 2−2α α α ….. Moles at equilibriumTotal no. of moles =2−2α+α+α=2 .
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