If 6.3 g of NaHCO3 are added to 15.0 g of CH3COOH solution, the residue is found to weigh 18.0 g. What is the mass of CO2 released in this reaction?

Mass of CO2=xg (say); wt. of NaHCO3 = 6.3g; wt. of CH3COOH = 15.0 g; wt. of residue CH3COONa and water = 18.0 g. The reaction is:  NaHCO3+CH3COOH⟶CH3COONa+H2O+CO2  6.3g15.0g18gxg.According to law of conservation of mass, weight of reactants is equal to weight of products. ∴ 6.3+15=18+x or x=6.3+15−18=3.3g Ans.