First slide

Gaseous state

Question

If 4 g of oxygen diffuse through a very narrow hole, how much hydrogen would have diffused under identical conditions?

Moderate

A

16 g
B

1 g
C

$\frac{1}{4} g$
D

64 g

Solution

$\frac{r_{H_{2}}}{r_{O_{2}}} = \sqrt{\frac{32}{2}} = 4 r_{H_{2}} = 4 r_{O_{2}} = 4 \times \frac{4}{32} {molH}_{2} = \frac{4 \times 4 \times 2}{32} {gH}_{2} = 1 g$

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