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Q.

If 10 g of V2O5 is dissolved in acid and is reduced to V2+ by zinc metal, how many moles of  iodine, could be reduced by the resulting solution if it is further oxidised to VO2+ ions ? (V = 51, O = 16, I = 127) :

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a

0.11 mole of I2

b

0.22 mole of I2

c

0.055 mole of I2

d

0.44 mole of I2

answer is A.

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Detailed Solution

Mole of V2O5=1051×2+5×16=10102+80=10182=.055 Mole of V+2=0.055×2=0.1098 mole ≃0.11V+2⟶VO+2+2eI2+2e⟶2I−⇒ Moles of I2= Moles of V+2=0.11
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