If 27 gram of Carbon is mixed with 88 gram of Oxygen and is allowed to burn to produce CO2 then:

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Limiting reagent is oxygen

C and O combine in mass ratio 3 : 8

Volume of unreacted O2 at STP is 11.2 L

Both ‘2’ and ‘3’

answer is D.

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Detailed Solution

C+O2→CO2 12 gram of carbon combines with 32 gram of oxygen to form 44 gram of Carbon dioxide.Then 27 gram of carbon combine with 27×3212gram of oxygen = 72 grams Oxygen is in excess, so oxygen is excess reagent and carbon is limiting reagent.Combining mass ratio of and O= 12: 32 = 3: 8 At STP 32 gram of O2 occupy = 22.4 LThen, 72 gram of O2 occupy = 72×22.432=50.4 litreBut given mass of O2=88 gramsVolume of 88 grams of O2 at STP =88×22.432=61.6 litre of O2 ∴Unreacted volume of oxygen, O2=61.6−50.4=11.2 litre

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