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Q.

If for H2(g) + 12 S2(g) ⇌ H2S(g) and H2(g) + Br2(g) ⇌ 2HBr(g)The equilibrium constants are K1 and K2 respectively, the reactionBr2(g) + H2S(g)  ⇌ 2HBr(g) +12 S2(g) would have equilibrium constant

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a

K1 × K2

b

K1 / K2

c

K2 / K1

d

K22 / K1

answer is C.

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Detailed Solution

K1=H2SH2 S21/2 ; K2=HBr2H2 Br2 K3=HBr2 × S21/2Br2 × H2S ; K2K1=K3
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If for H2(g) + 12 S2(g) ⇌ H2S(g) and H2(g) + Br2(g) ⇌ 2HBr(g)The equilibrium constants are K1 and K2 respectively, the reactionBr2(g) + H2S(g)  ⇌ 2HBr(g) +12 S2(g) would have equilibrium constant