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Q.

If the hydrogen electrode is dipped in a solution of pH = 2 at 25° C, then the reduction potential of the electrode would be

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a

0.118 V

b

0.084 V

c

0.059 V

d

-0.118 V

answer is D.

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Detailed Solution

H++e−→12H2(g) ∴EH+/H2=E0H+/H2−0.05911log1H+ =0−0.05911log10-2= – 0.0591 × 2 = – 0.118V
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