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If the ionization energy of He+ is 19.6 × 10-18 J per atom then the energy of Be3+ ion in the second stationary state is:

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By Expert Faculty of Sri Chaitanya
a
−4.9×10−18J
b
−44.1×10−18 J
c
−11.025×10−18 J
d
None of these

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detailed solution

Correct option is D

EH in first orbit =−19.6×10−184EBe3+ in second orbit=−19.6×10−184×164=-19.6×10−18 J


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