If the ionization energy of He+ is 19.6 × 10-18 J per atom then the energy of Be3+ ion in the second stationary state is:

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−4.9×10−18J

−44.1×10−18 J

−11.025×10−18 J

None of these

answer is D.

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Detailed Solution

EH in first orbit =−19.6×10−184EBe3+ in second orbit=−19.6×10−184×164=-19.6×10−18 J

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