If Kh (hydrolysis constant) for anilinium ion is 2.4 × 10-5M, then Kb for aniline will be
4.1 × 1010
4.1 × 10-10
2.4 × 109
2.4 × 10-19
Kh for anilinium ion = 2.4 × 10-5 M
Kh = KwKb
Kb = 10-142.4 ×10-5 =4.1 ×10-10